Angular acceleration of a drill

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SUMMARY

The discussion focuses on calculating the angular acceleration of a dentist's drill that starts from rest and reaches a rotational speed of 2.20 x 104 rev/min after 2.90 seconds of constant angular acceleration. The correct conversion of revolutions per minute to radians per second is essential, resulting in an angular velocity of 2303.8 rad/sec. The user initially calculated the angular acceleration as 886.09 rad/sec2 but received an incorrect response from WebAssign, indicating a potential error in their calculations.

PREREQUISITES
  • Understanding of angular kinematics
  • Knowledge of unit conversion between revolutions per minute and radians per second
  • Familiarity with the equations of motion for rotational dynamics
  • Basic proficiency in using online homework submission systems like WebAssign
NEXT STEPS
  • Review the conversion process from rev/min to rad/sec for accuracy
  • Study the equations of motion for rotational systems, focusing on angular acceleration
  • Practice similar problems involving constant angular acceleration
  • Explore troubleshooting techniques for online homework platforms like WebAssign
USEFUL FOR

Students studying physics, particularly those focusing on rotational dynamics, as well as educators looking for examples of angular acceleration problems.

Dr_bug
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Homework Statement


A dentist's drill starts from rest. After 2.90 s of constant angular acceleration it turns at a rate of 2.20 x 10^4 rev/min.
(a) Find the drill's angular acceleration (in rad/sec^2).
(b) Determine the angle (in radians) through which the drill rotates during this period.

Homework Equations





The Attempt at a Solution


okay so for (a) I thought that I should convert the rev/ min to rad/sec first and got 2303.8 rad/sec and then I used: change in angular velocity/ change in time and got 886.09 but when I input this answer, webassign (thats how we submit homework) says I'm wrong... I don't know what else to try
 
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Dr_bug said:

Homework Statement


A dentist's drill starts from rest. After 2.90 s of constant angular acceleration it turns at a rate of 2.20 x 10^4 rev/min.
(a) Find the drill's angular acceleration (in rad/sec^2).
(b) Determine the angle (in radians) through which the drill rotates during this period.

Homework Equations





The Attempt at a Solution


okay so for (a) I thought that I should convert the rev/ min to rad/sec first and got 2303.8 rad/sec and then I used: change in angular velocity/ change in time and got 886.09 but when I input this answer, webassign (thats how we submit homework) says I'm wrong... I don't know what else to try

Are you using 2.9 s for your time? Check your division.
 
Ahh Geez... thanks I was going crazy
 

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