How Long Does It Take for a Motor to Stop Due to Bearing Friction Alone?

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The discussion focuses on calculating the time it takes for a motor's armature to stop due to bearing friction. The armature of a shunt motor, with a mass of 250 kg and a diameter of 30 cm, has a rotational inertia of 2.81 Kg-m². When the armature accelerates under a constant torque of 120 N-m, it reaches a speed of 3000 rpm in 7.35 seconds. The torque of friction from the bearings is calculated at 0.314 N-m, leading to a stopping time of 420 seconds when power is cut off.

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calculate the time?

Need help with answer #3 and #7 Use the others for information.
Thanks!

1) The armature of a shunt motor has a mass of 250 kg and a diameter of 30 cm. Assume the mass of the armature is evenly distributed in the armature. Find the rotational inertia of the armature.
Ans. 2.81 Kg-m^2

2) How fast will the unloaded armature accelerate in coming up to speed if the armature current is so regulated that the armature developes a constant torque of 120 N-m?
Ans. 42.7 rad/sec^2

3) Assume the torque stays constant at 120 N-m. How long will it take for the unloaded armature to accelerate from zero up to full speed of 3000 rpm?
a. 7.35 sec
b. 34.1
c. 70.2
(my answer is c..am i correct?)

4) What horsepower is developed by the motor while running at 3000 rpm and delivering a torque of 120 N-m to a load?
Ans. 50.5 hp

5) If the power to the motor is shut off while the motor is running at 3000rpm and a brake is applied, how much heat in joules will be dissipated in the brake in order to bring the motor to a stop?
Ans. 138,527 J

6) Suppose the motor has a bearing shaft diameter of 3.2 cm and the coefficient of friction of each bearing is 0.008. find the torque of friction of the bearings.
Ans. 0.314

7)referring to problem 5, suppose that, instead of the brake being applied, the motor with the power cut off is allowed to run until it is brought to a stop by the torque of friction of the bearings. how long will the armature take to come to a stop?assume all other losses (such as windage) are zero.
a. 420 sec
b. 1260 sec
c. 2810 sec
(my answer is a..am i correct?)
 
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It would be easier if you would show your work rather than just giving your answer. As a general rule, it takes less time to check work than it does to do the question oneself and then say whether you are right or wrong.
 

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