Angular Acceleration of a Moving Wheel

Click For Summary
SUMMARY

The discussion centers on calculating the angular acceleration of a cyclist's wheel, which makes 8.5 revolutions in 4.6 seconds. The correct approach involves first converting revolutions to radians, yielding an angular displacement of 53.41 radians. The angular velocity is then calculated as 11.61 rad/sec. To find the angular acceleration, the appropriate kinematic equation is w² = wi² + 2a(θ), where the initial angular velocity (wi) is zero, leading to an angular acceleration of 2.5 rad/sec².

PREREQUISITES
  • Understanding of angular displacement and its conversion from revolutions to radians.
  • Familiarity with the concept of angular velocity (omega) and its calculation.
  • Knowledge of kinematic equations for rotational motion.
  • Basic grasp of the concept of angular acceleration.
NEXT STEPS
  • Study the kinematic equations for rotational motion in detail.
  • Learn how to derive angular acceleration from angular velocity and time.
  • Explore the relationship between linear and angular motion.
  • Review problems involving angular acceleration to reinforce understanding.
USEFUL FOR

Students studying physics, particularly those focusing on rotational dynamics, as well as educators seeking to clarify concepts of angular motion and acceleration.

underoathP
Messages
5
Reaction score
0
I am having a bit of trouble with the following problem.

A cyclist starts from rest and pedals so that the wheels make 8.5 revolutions in the first 4.6 s. What is the angular acceleration of the wheels (assumed constant)?

I multiplied 8.5 by 2pi and then divided by 4.6 sec. I get an answer of 11.6 rad/sec, but they want an answer in rad/sec^2. Am I doing this right?
 
Physics news on Phys.org
underoathP said:
I am having a bit of trouble with the following problem.

A cyclist starts from rest and pedals so that the wheels make 8.5 revolutions in the first 4.6 s. What is the angular acceleration of the wheels (assumed constant)?

I multiplied 8.5 by 2pi and then divided by 4.6 sec. I get an answer of 11.6 rad/sec, but they want an answer in rad/sec^2. Am I doing this right?
I see you've found the Homework Forums, :wink:.

Not quite. What is the definition of angular acceleration?
 
Last edited:
Angular Acceleration

The definition of angular acceleration is angular velocity over time. So, to get angular velocity from 8.5 rev/4.6 sec you have to find the angular velocity first. So, the definition of angular velocity (omega) is angular displacement over time, and the angular displacement is in radians. That is why I multiplied 8.5 by 2pi. Do I have to divide by 4.6 again?
 
I looked at that website and this is what makes sense to me:

8.5 rev * 2pi = 53.41 radians
53.41 rad / 4.6 sec = 11.61 rad/sec (omega)
11.61 rad/sec / sec = 2.5 rad/sec^2

2.5 is the wrong answer when I entered it. I am out of ideas.
 
underoathP said:
I looked at that website and this is what makes sense to me:

8.5 rev * 2pi = 53.41 radians
53.41 rad / 4.6 sec = 11.61 rad/sec (omega)
11.61 rad/sec / sec = 2.5 rad/sec^2

2.5 is the wrong answer when I entered it. I am out of ideas.
Okay, how about this section of the website;

drot2.gif


Which equation do you suppose would be appropriate in this case?
 
wait what happened to this? was there an answer discussed? I am so confused! i have a very similar problem and I am doing the same thing.

I think the right equation is w^2= wi^2+2a(theta)

but i used that assuming the initial angular velocity is 0 and its wrong
 

Similar threads

Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
980
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K