Angular acceleration of dipole in uniform electric field

  • #1
cupid.callin
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1. The problem statement, and my attempt at a solution is given in pic

Please help me.
 

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  • #2
G01
Homework Helper
Gold Member
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At first glance, you're moment of inertia is incorrect. The rod is massless and therefore does not contribute to the moment of inertia. Your moment of inertia comes from the two massive point particles a distance, L/2, away from the center of rotation.
 
  • #3
cupid.callin
1,137
0
At first glance, you're moment of inertia is incorrect. The rod is massless and therefore does not contribute to the moment of inertia. Your moment of inertia comes from the two massive point particles a distance, L/2, away from the center of rotation.

Yes, so ...

moment of inertia, I = [tex]\sum m_ir_i^2[/tex] = [tex]\frac{ML^2}{4} \ + \ \frac{ML^2}{4}[/tex]

So [tex]I \ = \ \frac{ML^2}{2}[/tex]

Is that wrong?
 
  • #4
cupid.callin
1,137
0
someone help please
 

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