Angular acceleration of dipole in uniform electric field

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Homework Help Overview

The discussion revolves around the angular acceleration of a dipole in a uniform electric field, focusing on the moment of inertia related to the system's configuration. The original poster seeks assistance in understanding their approach to the problem.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the moment of inertia for a dipole system, considering the contributions from point masses and questioning the correctness of their calculations.

Discussion Status

Some participants have pointed out potential errors in the original poster's calculation of the moment of inertia, specifically regarding the assumption of a massless rod. There is an ongoing exploration of the correct formulation of the moment of inertia, with no clear consensus reached yet.

Contextual Notes

The discussion includes assumptions about the mass distribution of the dipole and the implications of using a massless rod in the calculations. The original poster's request for help indicates a need for further clarification on these points.

cupid.callin
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1. The problem statement, and my attempt at a solution is given in pic

Please help me.
 

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At first glance, you're moment of inertia is incorrect. The rod is massless and therefore does not contribute to the moment of inertia. Your moment of inertia comes from the two massive point particles a distance, L/2, away from the center of rotation.
 
G01 said:
At first glance, you're moment of inertia is incorrect. The rod is massless and therefore does not contribute to the moment of inertia. Your moment of inertia comes from the two massive point particles a distance, L/2, away from the center of rotation.

Yes, so ...

moment of inertia, I = [tex]\sum m_ir_i^2[/tex] = [tex]\frac{ML^2}{4} \ + \ \frac{ML^2}{4}[/tex]

So [tex]I \ = \ \frac{ML^2}{2}[/tex]

Is that wrong?
 
someone help please
 

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