How to Determine Angular Deceleration and Initial Speed of a Coasting Saw Blade?

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SUMMARY

The discussion focuses on calculating the angular deceleration and initial speed of a coasting circular saw blade that completes 1200 revolutions in 40 seconds. Using the equation for angular displacement, the initial angular speed is determined to be 30 RPM. The angular deceleration is calculated using the final velocity of 0 RPM and the time of 40 seconds, resulting in an angular deceleration of 0.75 RPM/s. These calculations assume constant deceleration throughout the coasting period.

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Lance WIlliam
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A circular saw blade completes 1200 revolutions in 40s while coasting to a stop after being turned off. Assuming constant deceleration, what are (a) the angular deceleration and (b) the initial angular speed?

Answer in RPM/S
Method I used: Change in theta is 1200
Time: 40s
final Vel.:0
Initial Vel.:?
Alpha:? Eqn Used: (change in theta)=(1/2)(Initial vel.+final vel.)*time
looking for inital speed:
1200=(1/2)(initial vel+0)40seconds
Take the vel. found and place into eqn:
looking for alpha:
final vel. =Initial vel.+alpha*time


I ended up getting 1.5 ...
 
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Lance WIlliam said:
looking for inital speed:
1200=(1/2)(initial vel+0)40seconds
This will give you the angular speed in rev/s.
Take the vel. found and place into eqn:
looking for alpha:
final vel. =Initial vel.+alpha*time
That will give you alpha in rev/s/s, not RPM/s like they want. (Convert the speed to RPM--rev/min, instead of rev/s.)
 

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