Angular frequency for Potential Energy Function

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SUMMARY

The discussion focuses on determining the angular frequency of a mass moving along the x-axis with the potential energy function U(x) = -U0 a^2 / (a^2 + x^2). The angular frequency is derived using the formula w^2 = k/m, where k is the spring constant obtained from the derivative of the potential energy. The solution reveals that for small oscillations, the angular frequency can be simplified to w = (2 U0 / m a^2)^(1/2) by approximating the gradient at x=0 and neglecting the x^2 term in the denominator.

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Homework Statement



A mass moves along the x-axis with potential energy
U(x)= - U0 a^2 / (a^2 + x^2). What is the angular frequency assuming the oscillation is small enough to be harmonic?



Homework Equations



w^2 = k/m with w as the angular frequency

F= -kx = -(gradient) U



The Attempt at a Solution



Since this is one-dimensional we take the derivative of U with respect to x.

I get -(gradient) U = -2 U0 a^2 x / (a^2 + x^2)^2

Therefore k= 2 U0 a^2 / (a^2 + x^2)^2

The correct answer does not have an x term in it.

w (omega) = k/m = (2 U0 / m a^2) ^ (1/2)

Is there a binomial expansion that would essentially eliminate the x term in the denominator?

Thanks for any help.
 
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The oscillation happens around x=0, so you can approximate the gradient there and neglect the x^2. That is exactly the approximation required by the problem statement.
 

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