1. The problem statement, all variables and given/known data You have a lens with f=1m. You decide to make a camera to take a picture of the solar eclipse. The image of the sun and its corona have an angular size of 1.00 degrees. Find the diamter (in cm) of the resulting image. 2. Relevant equations M=theta'/theta = 25cm/f 3. The attempt at a solution I decided to find the angular magnification: M=25cm/100cm = 1/4 (so the image the camera observes is smaller than what is in the sky?) And since M=theta'/theta and I know theta=1.00 degree, I figured I'd find theta': theta'=M*theta = 0.25 degrees And I thought I'd get the height of the image formed using just a triangle where one angle is .25 degrees and one of the sides is the near point distance of 25 cm. Which yielded image height of about 1.1mm.... Is this method right? I don't like how the height is so tiny. But I remember that when you focus sunrays with a magnifying glass you get a point (to burn whatever), so at the same time it doesn't seem unreasonable. Any help would be greatly appreciated.