How Do You Calculate Angular Magnification for a Lens?

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To calculate angular magnification for a lens, the correct formula is M = -di/do, where di is the image distance and do is the object distance. In this case, with an object distance of 5.37 cm and an image distance of -66.7 cm, the angular magnification is calculated as M = -(-66.7 cm)/5.37 cm, resulting in a magnification of 12.4. This indicates that the insect appears 12.4 times larger through the lens than its actual size. The formula M = N/f + 1 is for linear magnification, not angular magnification. Understanding the distinction between these formulas is crucial for accurate calculations.
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Hi; Could someone please help me with this question: A small insect is placed 5.37 cm from a +5.84 cm focal length lens. a) Calculate the position of the image. b) Calculate the angular magnification.
For part a I used the lens equation 1/f = 1/d object + 1/d image, and I the position of the image to be -66.7cm...which is correct. However I can't get the right answer for the angular magnification. I used this equation: M =N/f + 1, but it doesn't give me the right answer. Can someone please help me with how to calculate angular magnification? Thanks.
 
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angular magnification is defined by the equation m = 25 / f i believe you are using the equation for max magnification
 


Angular magnification is a measure of how much larger an object appears through a lens compared to its actual size. It is calculated using the formula M = -di/do, where di is the image distance and do is the object distance.

In this case, the object distance is 5.37 cm and the image distance is -66.7 cm (since it is a virtual image formed by a converging lens). Therefore, the angular magnification is M = -(-66.7 cm)/5.37 cm = 12.4. This means that the insect appears 12.4 times larger when viewed through the lens compared to its actual size.

Note that the formula you used, M = N/f + 1, is actually the linear magnification formula, where N is the height of the image and f is the focal length. This formula is used when calculating the size of the image formed by a lens, rather than the apparent size of the object.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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