The question: Consider two masses of 0.1 gm each, connected by a rigid rod of length 0.5 cm, rotating about their center of mass with an angular frequency of 800 rad/s. a.) What is the value of l corresponding to this situation? b.) What is the energy difference between adjacent l-values for the l you have just calculated? Relevant equations: Moment of Intertia about center of mass = ∑miri L=I * ω L= ħ[l(l+1)]1/2 My attempt at part a of the problem: r= 0.0025m mass= 0.0001 kg I = 2 * (0.0001 kg) * (0.0025 m2) = 1.25 * 10-9 kg m2 L = 1.25 * 10-9 kg m2 * 800 rad/s L/ħ = 9.48*1027 = [l(l+1)]1/2 Which this is the answer, but when I solve for l(the quantum number for angular momentum) I get a number with order of magnitude of 1055 am I completely overlooking something here? I can't think of any other ways to solve this problem. Thank you in advance for your help!