- #1

krawls30

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Move here from another forum, so no homework template.

The question: Consider two masses of 0.1 gm each, connected by a rigid rod of length 0.5 cm, rotating about their center of mass with an angular frequency of 800 rad/s.

Relevant equations:

Moment of Intertia about center of mass = ∑m

L=I * ω

L= ħ[

My attempt at part a of the problem:

r= 0.0025m

mass= 0.0001 kg

I = 2 * (0.0001 kg) * (0.0025 m

L = 1.25 * 10

L/ħ = 9.48*10

Which this is the answer, but when I solve for l(the quantum number for angular momentum) I get a number with order of magnitude of 10

**a.)**What is the value of*l*corresponding to this situation?**b.)**What is the energy difference between adjacent*l*-values for the*l*you have just calculated?Relevant equations:

Moment of Intertia about center of mass = ∑m

_{i}r_{i}L=I * ω

L= ħ[

*l*(*l*+1)]^{1/2}My attempt at part a of the problem:

r= 0.0025m

mass= 0.0001 kg

I = 2 * (0.0001 kg) * (0.0025 m

^{2}) = 1.25 * 10^{-9}kg m^{2}L = 1.25 * 10

^{-9}kg m^{2}* 800 rad/sL/ħ = 9.48*10

^{27}= [*l*(*l*+1)]^{1/2}Which this is the answer, but when I solve for l(the quantum number for angular momentum) I get a number with order of magnitude of 10

^{55}am I completely overlooking something here? I can't think of any other ways to solve this problem. Thank you in advance for your help!