# Angular momentum/ energy conservation.

## Homework Statement

A block of mass 7.00×10-1kg is suspended by a string which is wrapped so that it is at a radius of 6.00×10-2m from the center of a pulley. The moment of inertia of the pulley is 5.70×10-3kg*m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D=0.790m is 1.233m/s. Calculate the amount of energy dissipated up to that point.
I set up an equation like this:
mgh=1/2mv^2+mg(h final)+1/2iw^2+L(energy loss) This makes sense to me... Why does this not work correctly?

## The Attempt at a Solution

mgh=1/2mv^2+mg(h final)+1/2iw^2+L(energy loss) This makes sense to me... Why does this not work correctly?

tiny-tim
Homework Helper
Welcome to PF!

Hi Roland of G! Welcome to PF! (have an omega: ω and try using the X2 icon just above the Reply box )
mgh=1/2mv^2+mg(h final)+1/2iw^2+L(energy loss) This makes sense to me... Why does this not work correctly?

It should work. Show us the figures. 