Angular momentum/ energy conservation.

  • #1

Homework Statement


A block of mass 7.00×10-1kg is suspended by a string which is wrapped so that it is at a radius of 6.00×10-2m from the center of a pulley. The moment of inertia of the pulley is 5.70×10-3kg*m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D=0.790m is 1.233m/s. Calculate the amount of energy dissipated up to that point.
I set up an equation like this:
mgh=1/2mv^2+mg(h final)+1/2iw^2+L(energy loss) This makes sense to me... Why does this not work correctly?


Homework Equations





The Attempt at a Solution


mgh=1/2mv^2+mg(h final)+1/2iw^2+L(energy loss) This makes sense to me... Why does this not work correctly?
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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Welcome to PF!

Hi Roland of G! Welcome to PF! :smile:

(have an omega: ω and try using the X2 icon just above the Reply box :wink:)
mgh=1/2mv^2+mg(h final)+1/2iw^2+L(energy loss) This makes sense to me... Why does this not work correctly?

It should work. :confused:

Show us the figures. :smile:
 

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