- #1

AirChambz

- 13

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## Homework Statement

A steel ball fastened to the end of a 1.5 m long string to form a pendulum is

released in the horizontal position. At the bottom of its swing, the ball collides elastically

with a block of equal mass resting on a frictionless surface. What is the speed of the block

just after the collision?

http://img686.imageshack.us/img686/3459/phys.png

R=1.5m

M_ball_=M_block_

## Homework Equations

I=mr^2

L_A_=r*p*sin(theta)

L_A_=I(omega)

## The Attempt at a Solution

I did not know where to start however I tried equating I(omega)=r*p*sin(theta) since momentum is conserved the momentum of the pendulum should turn into the momentum of the block, also since the masses are equal whatever final momentum you get should be the answer

Anyway the answer turns out to be 5.4 m/s in the end just am not able to get there...

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