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Angular momentum of a particle with a symmetrical path
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[QUOTE="vidit jain, post: 5451217, member: 557371"] Since the angular momentum depends on then cross product of the position vector and momentum vector(which is in the same direction as velocity),the formulae for the angular momentum maybe written as mvr[SUB]perpendicular[/SUB]. (The cross product of the component of r vector along/parallel to velocity/momentum is 0) Find the perpendicular distance of the velocity vector from the origin.for eg in the first case it is 0 since the velocity vector passes through the origin and in the second case it is the max height of the projectile. [/QUOTE]
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Angular momentum of a particle with a symmetrical path
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