Angular Momentum of a sanding disk

[Destrio]

A sanding disk with rotational inertia 1.22x10^-3 kgm^2 is attached to an electric drill whose motor delivers a torque of 15.8 Nm
a) find angular momentum
b) find angular speed of the disk 33.0ms after the motor is turned on.

L = Iω
τ = Iα

we can find angular acceleration with what we are given α = τ/I
but I'm completely stumped on how to find L without having time.
any hints?

thanks

 

[Doc Al]

Here's a hint: You are given the time!

 

[Ojizo88]

Here's a hint: You are given the time!

lol man I stared at that over and over again and thought, "I must be misreading this...wheres the trick?"

But seriously, yes you are given the time. its "33.0ms" part

 

[Destrio]

Haha, thanks
I realized from that that I can use the time to solve the first part of my problem.

L = Iω

L =τω/α
ω = αt
L =τt

that works

τt = Iω
ω = τt/I
which gives me 427m/s
but i need the answer in rev/min
im okay with seconds to minutes, but how do i convert meters to revolutions?
2pi?

 

[Ojizo88]

If you can find its angular acceleration, then ( just like linear kinematics... ) its angular velocity is equal to its angular acceleration multiplied by the duration of the acceleration.

 

[Doc Al]

τt = Iω
ω = τt/I
which gives me 427m/s

The units for ω are radians/sec, not m/s. One revolution equals $2 \pi$ radians.

 

[Destrio]

woo i got it!

thanks