1. The uniform bar shown in the diagram has a length of 0.80 m. The bar begins to rotate from rest in the horizontal plane about the axis passing through its left end. What will be the magnitude of the angular momentum of the bar 6.0 s after the motion has begun? The forces acting on the bar are shown. 2. L = Iw, L = I(alpha)t 3. I know that I = (1/3)mL^2 = 16m/75 So, L = (16m/75)*6sec*alpha Am I going about this correctly so far? How do I bring the forces into the equation?