Angular Momentum of Ice Skater: 881.93kg m2/s

[joebob]

Homework Statement

An ice skater with a mass of 55.5kg is holding on to the end of a 3.75 m long rope tha is attached to a pole protruding out of a frictionless ice covered pond. Intially the skater is making one revolution every 5.44seconds.
What is the initial angular momentum of the skater?

A) 780kg m²/s
B) 901kg m²/s
c) 11,200 kg m²/s
d) 18600 kg m²/s

Homework Equations

The Attempt at a Solution

I have found the moment of interia, which i found to be 780.47kg m²
I found the angular velocity to be 1.13rad/s
The answer i get is not one of the options. I get 881.93kg m²/s

 

[ideasrule]

It's just a rounding error.

 

[joebob]

What step is my error in? i have been redoing to equations and keep getting the same

 

[ideasrule]

Angular velocity is more like 1.15 rads/sec. How did you get 1.13? 1 rev=2*pi, and 2*pi/5.44=1.155 rad/sec

 

[joebob]

i did x/1=1/5.44 to get .18revolutions a second and then multiplied that by 2pie to convert to radians a second
i found my error while doing this it was a rounding error thanks for the help