Angular momentum of orbit from orbit parameters and mass of sun

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The discussion revolves around calculating the angular momentum of a planet in an elliptical orbit around the sun, using parameters such as the semi-major axis (a) and semi-minor axis (b). The derived angular momentum formula, L = √(GM m² b²/a), is compared to the provided answer, L = √(2GM m² ab/(a+b)), leading to confusion about the inconsistency. It is clarified that the discrepancy arises because the given answer assumes a circular orbit, which simplifies the calculations. Ultimately, when a equals b, both formulas yield consistent results, highlighting the importance of recognizing orbital shapes in angular momentum calculations.
Kaguro
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Homework Statement
A planet of mass m moves in the gravitational field of sun ( mass M). If semi major and minor axes are a and b respectively, the angular momentum of the planet is what?
Relevant Equations
Area of ellipse ##\pi ab##

Kepler's laws
L = mvr = mr (dr/dt) = 2m*r*(dr/dt)/2 = 2m*(dA/dt)
So, A = (L/2m)T
so, ## L = \frac{2 \pi a b m}{T}##

Now, ##T^2 = \frac{4 \pi^2}{GM} a^3##
So from all these, I get
##L = \sqrt{ \frac{GM m^2 b^2}{a}}##

But answer given is
##L = \sqrt{ \frac{2GM m^2 ab}{a+b}}##
(This, they have derived from energy and angular momentum conservation.)

What is wrong? Where's this inconsistency coming from?
 
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Kaguro said:
Homework Statement:: A planet of mass m moves in the gravitational field of sun ( mass M). If semi major and minor axes are a and b respectively, the angular momentum of the planet is what?
Relevant Equations:: Area of ellipse ##\pi ab##

Kepler's laws

L = mvr = mr (dr/dt) = 2m*r*(dr/dt)/2 = 2m*(dA/dt)
So, A = (L/2m)T
so, ## L = \frac{2 \pi a b m}{T}##

Now, ##T^2 = \frac{4 \pi^2}{GM} a^3##
So from all these, I get
##L = \sqrt{ \frac{GM m^2 b^2}{a}}##

But answer given is
##L = \sqrt{ \frac{2GM m^2 ab}{a+b}}##
(This, they have derived from energy and angular momentum conservation.)

What is wrong? Where's this inconsistency coming from?
I prefer your answer. So does this:

https://www.lehman.edu/faculty/anchordoqui/chapter25.pdf

See equation 25.B.20.

Why didn't you find that pdf? :wink:
 
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Cant find a mistake in your answer either.

Just to rewrite your first line using cross product because the way it is written as simple multiplication is wrong
$$\vec{L}=m\vec{r}\times\frac{d\vec{r}}{dt}=2m\frac{1}{2}\vec{r}\times\frac{d\vec{r}}{dt}\Rightarrow |\vec{L}|=2m\frac{dA}{dt}$$ where ##A## is the area that the radius vector ##\vec{r}## spans.
 
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Ah...

I now realize that the answer given is wrong, because they assumed the orbit is circular.
When I put a=b, the two answers are consistent.

But even after assuming that a=b, they still wrote them as though they are different.

Thank you both of you.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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