One can represent the mean of the angular momentum operator as a vector. But(adsbygoogle = window.adsbygoogle || []).push({}); what is the (mathematical) justificationto represent the operator by a vector which has a direction that the operator has not. Yet worse, l(l+1) h2 is the proper value of operatorL^2and fromsuch resultit is assumed that (l(l+1))^1/2 is the length of operatorL. Such trick-representation seems to be a strong convention, but it does not make it mathematically correct.

**Physics Forums - The Fusion of Science and Community**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Angular momentum operator justification

Loading...

Similar Threads - Angular momentum operator | Date |
---|---|

I Measurement Values for z-component of Angular Momentum | Nov 18, 2017 |

I Adding types of angular momenta | May 14, 2017 |

I Angular momentum operator commutation relation | May 10, 2017 |

I Angular momentum raising/lowering operators | Mar 23, 2017 |

A What are L+ and L- matrices for l=3 ? | Jan 9, 2017 |

**Physics Forums - The Fusion of Science and Community**