Angular mometum and the commutator?

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SUMMARY

The discussion focuses on proving the commutation relation [L_z, L_x] = i(ħ)L_y using angular momentum operators in quantum mechanics. The operators L_z and L_x are defined in terms of position and momentum, specifically L_z = xP_y - yP_x and L_x = -iħ(y∂/∂x - z∂/∂y). Participants emphasize the importance of using operator identities such as [A, B+C] = [A, B] + [A, C] and [A, BC] = [A, B]C + B[A, C] to simplify the algebraic manipulation required to derive the desired result.

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cragar
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Homework Statement


show that
<br /> [L_z,L_x]=i(\hbar)L_y<br />

The Attempt at a Solution



[A,B]=AB-BA
<br /> L_z=xP_y-yP_x<br />
<br /> L_x=yP_z-ZP_x<br />
So do i just use the fact that [A,B]= AB-BA
and then use the momentum operators and substitute everything in an churn out the algebra to reduce it down.
 
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You already know what the operators L_x,\ L_z are defined as in terms of differentials.

For example, L_x = -i\hbar\left(y\frac{\partial}{\partial x} - z\frac{\partial}{\partial y}\right)

Just make use of the following operator identities:

[A,B+C] = [A,B]+[A,C]
[A,BC] = [A,B]C+B[A,C]

and you should be able to manipulate them into what you want. I'm not sure [A,B] = AB - BA would have been sufficient in and of itself.
 
thanks for your response
 

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