Angular position for 2nd order diffraction

  • Thread starter Bolter
  • Start date
  • #1
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Homework Statement:

See image attached below

Relevant Equations:

dsin(theta) = m*lambda
Here is my problem

Screenshot 2020-03-23 at 20.17.40.png


I have given this a go and get 26.77 degrees as my angular position

IMG_4328.JPG


My concern is do I double this angle to get the angular width between both 2nd order maxima's (which would be 53.53 degrees) or do I just leave it as 26.77 degrees?

Thanks for any help!
 

Answers and Replies

  • #2
TSny
Homework Helper
Gold Member
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Looks good. I believe they are asking for the angle between the central max and either of the 2nd order maxima.
 
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