Angular speed and tangential velocity

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Angular speed is always smaller in magnitude than tangential velocity due to the larger distance tangential velocity covers in the same time frame. Tangential velocity depends on both the radius and the angular speed, with the formula v = ωr illustrating this relationship. While angular speed is measured in radians per second and tangential velocity in meters per second, direct comparisons of their magnitudes are not meaningful because they are different quantities. The linear speed of a particle in circular motion increases with radius, confirming that the outer edge of circular motion moves faster than the center. Understanding the conversion between these two speeds is essential for accurate comparisons in different units.
lonewolf219
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i am wondering if this is correct...

The angular speed is always a smaller magnitude than the tangential velocity. This is because the tangential velocity has to travel a larger distance during the same amount of time as the angular speed. Tangential velocity is dependent on two things: the extra distance it covers (radius) compared to the central angular speed, and the magnitude of the angular speed.

Sound right or only partially?
 
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Angular speed and tangential velocity are two different animals with different units. You cannot meaningfully compare their magnitudes.

Angular speed = radians/sec

Tangential velocity = meters/sec
 
You are considering a rigid body in purely rotational motion...circular motion, right?

This part seems ok:
The angular speed is always a smaller magnitude than the tangential velocity..

although I think you mean:

"The angular speed is always a smaller magnitude than the MAGNITUDE of the tangential velocity..."

but from there your description makes no sense to me.

The linear speed of a particle in circular motion is the product of the angular speed and the distance (r) from the axis of rotation...v = wr. So v is greater than w except at r = o.

When these are considered as vectors, v and w are othogonal so "magnitude" comparsions are somewhat moot...for uniform circular motion, the angular velocity vector w remains fixed in direction along the axis of rotation...while the velocity vector v direction changes direction at a constant rate.
 
Yes, they do have different units.

It is true, though, the concept that the speed on the outer edge of circular motion is faster than the center speed? Is that why there are different speeds for the Earth's rotation at various distances from the equator?
 
Naty1 said:
The linear speed of a particle in circular motion is the product of the angular speed and the distance (r) from the axis of rotation...v = wr. So v is greater than w except at r = o.
For what it's worth, the numerical value of v will be less than the value of ω whenever r < 1.
 
lonewolf219 said:
It is true, though, the concept that the speed on the outer edge of circular motion is faster than the center speed?
The tangential speed for larger radii is greater than the tangential speed at a smaller radii. Note that you are comparing tangential speeds, not angular versus tangential.
 
Ah, OK. Thanks Doc Al. That is true for tangential velocities.
 
You can convert one into the other using a suitable conversion factor - from Doc's units you can see that this should be something converting radians (no unit) to meters (length).

For example, for a spinning disc with radius R, for a point on the disc at distance r from the origin the formula is
v = \omega r
where v is the tangential velocity and \omega is the angular velocity.

As Doc remarked though, the numbers themselves don't mean anything.
If you decide to measure v in mph, omega in degrees/century and r in inches, you will get completely different numerical values.

[edit]Wow, you guys are fast. Never mind my post - it's a bit obsolete by now!
 

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