Angular Velocity: Formula for Max Velocity of Wood Block

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SUMMARY

The discussion focuses on deriving the formula for the maximum velocity of a wood block (V_B) when a steel plate moves along a steel table. The block's velocity in the downward direction is expressed as V_B = vcos(θ)sin(θ), where v is the velocity of the plate and θ is the angle of inclination. To find the angle that maximizes V_B, one must differentiate this expression with respect to θ and set the derivative to zero. Alternatively, trigonometric methods can also be employed to determine the maximum value of V_B.

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Brett bALL
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This is my first contact and please excuse my limited knowledge of physics.
see attached sketch.
If the steel plate is moved along the steel table in direction A at a given velocity, what is the formula for the angle to achieve maximum velocity of the wood block in direction B.
 

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Hi,

Im assuming that you have a basic knowledge of calculus.

If you assume that the plate moves in the direction A with a velocity v, then the block moves with a velocity [tex]vcos(\theta)[/tex] along the plank in the downward direction.

The projection of this velocity along the B and A direction is [tex]vcos\thetasin\theta[/tex] and [tex]vcos\thetacos\theta[/tex]

[tex]V_B=vcos(\theta)sin(\theta)[/tex]
Differentiate this expression wrt [tex]\theta[/tex] and equate to zero to get max value.

Otherwise, you can find the max value of Vb using trig.
 

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