# Angular Velocity of a Car going around a curve

## Homework Statement:

A car taking going through a curve of radius 60.0 meters that turns the car through a horizontal ground angle of 90 degrees, if the car goes through the 90 degree curve in a time of 5 seconds, what is the car's Angular Velocity around the curve in radians per second?

## Relevant Equations:

ω=dθ/dt
θ=90°= π /2 so the instantaneous angular velocity dθ/dt= lim t -> 0 (θ(t + t)-θ(t))/( t)

When I calculate it out it is π /2 radians per second. Is this correct?

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BvU
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Hi, and !

When a 90 degrees turn is done in 5 seconds the ##\omega## can not be ##\pi/2## per second.

How many degrees per second is that ?

Hi, and !

When a 90 degrees turn is done in 5 seconds the ##\omega## can not be ##\pi/2## per second.

How many degrees per second is that ?
90, thats why I'm confused.

BvU
Homework Helper
2019 Award
So how many radians per second if ##\pi/2## radians take 5 seconds (and you may asssume constant speed) ?

The car is going around a curve so I assumed a constant change in velocity, or would it be constant?
If constant π /10

BvU
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2019 Award
Direction of the velocity vector changes, but its magnitude (what the speedometer indicates) is constant.

Direction of the velocity vector changes, but its magnitude (what the speedometer indicates) is constant.
Thank you!

• berkeman
BvU
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You're welcome !

BvU
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2019 Award
So what is your conclusion ?

BvU