# Angular Velocity of a Car going around a curve

RobGoodall
Homework Statement:
A car taking going through a curve of radius 60.0 meters that turns the car through a horizontal ground angle of 90 degrees, if the car goes through the 90 degree curve in a time of 5 seconds, what is the car's Angular Velocity around the curve in radians per second?
Relevant Equations:
ω=dθ/dt
θ=90°= π /2 so the instantaneous angular velocity dθ/dt= lim t -> 0 (θ(t + t)-θ(t))/( t)

When I calculate it out it is π /2 radians per second. Is this correct?

Homework Helper
Hi, and !

When a 90 degrees turn is done in 5 seconds the ##\omega## can not be ##\pi/2## per second.

How many degrees per second is that ?

RobGoodall
Hi, and !

When a 90 degrees turn is done in 5 seconds the ##\omega## can not be ##\pi/2## per second.

How many degrees per second is that ?
90, that's why I'm confused.

Homework Helper
So how many radians per second if ##\pi/2## radians take 5 seconds (and you may asssume constant speed) ?

RobGoodall
The car is going around a curve so I assumed a constant change in velocity, or would it be constant?
If constant π /10

Homework Helper
Direction of the velocity vector changes, but its magnitude (what the speedometer indicates) is constant.

RobGoodall
Direction of the velocity vector changes, but its magnitude (what the speedometer indicates) is constant.
Thank you!

berkeman
Homework Helper
You're welcome !