Angular Velocity of a turntable-man system

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Homework Help Overview

The problem involves a turntable rotating about a fixed vertical axis, with a man running outward from the center. It focuses on angular velocity, angular momentum, and moment of inertia in a rotational dynamics context.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate initial angular velocity and angular momentum, expressing uncertainty about the calculation of angular velocity when the man is 2m from the center. Some participants question the method for recalculating inertia and the implications of angular momentum conservation.

Discussion Status

The discussion is ongoing, with some guidance provided regarding the conservation of angular momentum. Participants are exploring different interpretations of the inertia calculation and its relevance to the problem.

Contextual Notes

There is a focus on the assumption of no external torque acting on the system, which is critical for the conservation of angular momentum. The problem also involves specific values for mass and moment of inertia that are central to the calculations being discussed.

Kizaru
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Homework Statement


A turntable rotates about a fixed vertical axis, making one revolution in 10s. The moment of inertia of the turntable about the axis is 1600kgm^2. A man, James Bond, of mass 120kg, is at the center of the turntable and begins to run out along a radius of the device. Treat the man as a point object.


Homework Equations


L = Iw


The Attempt at a Solution


There are three parts. The first part asks for the initial angular velocity, which is simply converting 1rev/10s into rad/s. The second part asks for the initial angular momentum, which would be L = Iw?

The third part is asking for the angular velocity of the turntable-man system when the man is 2m from the center of the turntable. It also says at this point the man is at rest with respect to the turntable.

Now I run into my problems. I'm not too sure about how to calculate this, but one method I'm thinking of is recalculating the inertia to be 1600kgm^2 + mr^2 where m and r are referring to the man (so 120kg and 2m respectively). This would give an inertia of 1840kgm^2.

I thought about using L = r (cross) p, but solving for the linear momentum would mean finding Vtan = wr? How would I find w in this case?
 
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Since there is no external torque acting on the tern table, angular momentum remains constant.
 
I was considering that approach but wasn't sure. Thanks. However, my approach to the new inertia would be correct, I assume?
 
Yes.
 

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