Have you drawn a diagram?orangegalaxies said:Homework Statement:: What is the angular width between the second minima and second maxima on the same side of the central maxima if a wavelength of 650 nm passes through a slit of 3.0 x 10^-3m wide.
Relevant Equations:: sin theta = n(wavelength)/width
i feel like subbing the numbers into the equation isn't enough because of the second minima and maxima thing? not sure what to do... would appreciate any help.
Is 'theta' in your formula the angle for a maximum or for a minimum?orangegalaxies said:Relevant Equations:: sin theta = n(wavelength)/width
The angular width of a single slit diffraction pattern is the angle between the first minima on either side of the central maximum. It is given by the equation θ = λ/d, where θ is the angular width, λ is the wavelength of the incident light, and d is the width of the slit.
The angular width is inversely proportional to the width of the slit. This means that as the slit becomes narrower, the angular width increases. Conversely, as the slit becomes wider, the angular width decreases.
The angular width is directly proportional to the distance from the slit. This means that as the distance from the slit increases, the angular width also increases.
Yes, the angular width is directly proportional to the wavelength of the incident light. This means that as the wavelength increases, the angular width also increases.
The number of slits does not affect the angular width in a diffraction pattern. The angular width is only dependent on the width of the single slit and the wavelength of the incident light.