1.On the same axis sketch the graphs of y = (x-a)^-1 and y = 4|x-a| This part i have completed, the first equation has a horizontal asymptote at x = a, it being rectangular hyperbola. the second equation drawn too. 2. Solve (x-a)^-1 < 4|x-a|, giving your answers in a. Now the second part confuses me, because i am not sure where to start as its the first of its kind I've tackled with an arbitrary constant. usually to solve something like this i would multiply both sides by the denominator squared, to ensure that i haven't multiplied by a negative number. I have tried equating two equations to y, one having the positive modulus and another having the negative, but in the end i get a really peculiar expression. (and it doesn't match the one in the answer section ) please help! i haven't started my degree yet (Mathematics). so if my terminology is off could someone please help me out there too haha.