Another Addition of Vectors question.

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Sudhir's problem involves calculating his displacement after walking 0.40 km at 60.0° west of north and then 0.50 km due west. The correct approach requires breaking down the vectors into their x (west) and y (north) components using the cosine and sine functions. The solution indicates a final displacement of 0.87 km at 77 degrees west, highlighting a common mistake of mixing up the x- and y-components. Accurate calculations should maintain significant figures to ensure the final answer's precision. Understanding vector addition is crucial for resolving such displacement problems effectively.
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Homework Statement



Sudhir walks 0.40 km in a direction 60.0° west of north, then goes 0.50 km due west. What is his displacement?

Homework Equations



According to my textbook, the equations are:

Ax = A cos θ
Ay = A sin θ
Bx = B cos θ
By = B sin θ
θ = tan-1 opposite side/adjacent side

Source: http://www.jpopovich.com/file.php/19/phy_chap5.pdf on page 122.

The Attempt at a Solution



http://screensnapr.com/e/zuQNvk.png

Click to see full image.

Both my answers are wrong according to my textbook. Can someone tell me why / explain to me?

The real answer: 0.87km at 77 degrees west
 
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I think you mixed up adding the .5 west. It should go with the west component of the .4, which is the .35 to give you .85.

Keeping 2 digit accuracy in the work only gives you 1 digit accuracy in the final answer.
 
You seem to have mixed up the x- and y-components for the vector A. You have the correct equations, but you wrote the x-component as the y-component and vice versa.
 

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