Another Addition of Vectors question.

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SUMMARY

The discussion revolves around a physics problem involving vector addition, specifically calculating the displacement of Sudhir after walking 0.40 km at 60.0° west of north and then 0.50 km due west. The correct displacement is determined to be 0.87 km at an angle of 77 degrees west. Key errors identified include the misassignment of x- and y-components in the vector calculations, which led to incorrect answers. The equations used for resolving vectors, specifically Ax = A cos θ and Ay = A sin θ, were correctly referenced but applied incorrectly in this instance.

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Homework Statement



Sudhir walks 0.40 km in a direction 60.0° west of north, then goes 0.50 km due west. What is his displacement?

Homework Equations



According to my textbook, the equations are:

Ax = A cos θ
Ay = A sin θ
Bx = B cos θ
By = B sin θ
θ = tan-1 opposite side/adjacent side

Source: http://www.jpopovich.com/file.php/19/phy_chap5.pdf on page 122.

The Attempt at a Solution



http://screensnapr.com/e/zuQNvk.png

Click to see full image.

Both my answers are wrong according to my textbook. Can someone tell me why / explain to me?

The real answer: 0.87km at 77 degrees west
 
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I think you mixed up adding the .5 west. It should go with the west component of the .4, which is the .35 to give you .85.

Keeping 2 digit accuracy in the work only gives you 1 digit accuracy in the final answer.
 
You seem to have mixed up the x- and y-components for the vector A. You have the correct equations, but you wrote the x-component as the y-component and vice versa.
 

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