Another another more challenging log question.

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Homework Help Overview

The discussion revolves around a logarithmic equation involving variables x and y, specifically log6(5y − 5) = 4x^2 + 7. Participants are exploring the implications of rewriting logarithmic expressions in exponential form.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to rewrite the logarithmic equation in exponential form and are questioning the validity of their approaches. There is a focus on ensuring that the transformations maintain the integrity of the equation.

Discussion Status

The discussion is active, with participants providing feedback on each other's attempts. Some guidance has been offered regarding the proper form of equations, and there is an ongoing exploration of how to manipulate the logarithmic expression effectively.

Contextual Notes

There appears to be confusion regarding the transformation of the logarithmic equation into an exponential form, with participants questioning the correctness of the attempted solutions and the necessity of maintaining equation integrity throughout the process.

hibachii
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another another more challenging log question. :(

Homework Statement


log6(5y − 5) = 4x^2 + 7


Homework Equations



-

The Attempt at a Solution


6( x^2 + 6x+5 ) +1
 
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hibachii said:

Homework Statement


log6(5y − 5) = 4x^2 + 7


Homework Equations



-

The Attempt at a Solution


6( x^2 + 6x+5 ) +1

You started with an equation - you should end with an equation.

An equation of the form logb(M) = N can be rewritten as an exponential equation of the form M = bN.
 


isnt that what i did (given in the attempted solution)?
 


No. For one thing, what you wrote isn't an equation, and it should be. For another thing, what you wrote doesn't follow the same pattern as the exponential equation I wrote.
 


hibachii said:

Homework Statement


log6(5y − 5) = 4x^2 + 7


Homework Equations



-

The Attempt at a Solution


6( x^2 + 6x+5 ) +1

64x^2+7=5y-5
Take the log of both sides now.
log64x^2+7=log5y-5
(4x2+7)log6=log5y-5

From here, isolate for one of the variables and substitute it into the original equation. Solve for the other once that is done.
 


What is your question?
Taking the exponential of both sides and then the log again really defeats the purpose of getting anywhere...
 

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