The combined weight of a small boat and a hunter is 1200 N. The boat is initially at rest on a lake as the hunter fires 75 bullets, each of mass 0.006 kg. If the muzzle velocity of the rifle is 600 m/s and frictional forces between boat and water are neglected, what speed will be acquired by the boat?
m1v1 = m2v2
The Attempt at a Solution
The first thing I realized is that the total momentum before the bullets are fired is zero and so I realized the momentum after the bullets are fired is zero. So m1v1 = m2v2. Then I found the total momentum of the bullets by multiplying the momentum of one bullet by 75 the total number of bullets. Then I divided that number by 1200 to find the final velocity of the boat. I got .135 m/s and the answer is -2.21 m/s