Another Electromagnetic Induction Question

[Giuseppe]

Again, this is a problem I got in my AP Physics Class can anyone help? I would really appreciate any help. My teacher didn't explain this concept too well.

A metal bar with length L, mass m, and resistance R is placed on frictionless, metal rails that are inclined at an angle \theta above the horizontal. The rails have negligible resistance. A uniform magnetic field of magnitude B is directed downward. The bar is released from rest and slides down the rails.

a. What is the terminal speed of the bar?
b. What is the induced current in the bar when the terminal speed has been reached?
c. After the terminal speed of the bar has been reached, at what rate is electrical energy being converted to thermal energy in the resistance of the bar?
d. After the terminal speed has been reached, at what rate is work being done on the bar by gravity?


I attemped first to use the equations that
\varepsilon=BLv
i=\frac{\varepsilon}{R}
F_B=iLB.

After some substitutions I find
F= \frac{B^2L^2v}{R}
but what do I do next?

 

[Giuseppe]

I think I made a little progress. After drawing a force diagram, I think I could say that the magnetic force = the x component of the force of gravity(i split gravity into components rather than anything else). so then i said that:

mg\sin{\theta}= \frac{B^2L^2v}{R}

and then solved for v. Would this be right for the terminal velocity?

 

[thepatientmental]

To solve this problem, we can use the concept of electromagnetic induction. When a conductor moves through a magnetic field, an electric current is induced in the conductor. This current will experience a magnetic force, causing the bar to slow down until it reaches a terminal speed where the magnetic force is equal to the gravitational force.

a. To find the terminal speed, we can use the equation F_B = mg, where F_B is the magnetic force and mg is the gravitational force. We can rewrite this equation as B^2L^2v/R = mg, and solve for v to get the terminal speed v = mgR/B^2L^2.

b. To find the induced current, we can use the equation i = \varepsilon/R, where \varepsilon is the induced emf and R is the resistance of the bar. We can substitute in the value for \varepsilon from the first equation, \varepsilon = BLv, and solve for i to get i = BLv/R.

c. After the terminal speed has been reached, the bar is moving at a constant speed, so there is no change in kinetic energy. Therefore, all of the work done by the magnetic force is being converted into thermal energy in the resistance of the bar. The rate at which this energy is being converted can be calculated using the equation P = i^2R, where P is the power, i is the current, and R is the resistance. We can substitute in the values for i and R from part b to get P = (BLv/R)^2 * R = B^2L^2v^2/R.

d. After the terminal speed has been reached, the gravitational force is equal to the magnetic force, so the net work being done on the bar by gravity is zero. However, gravity is still doing work to maintain the bar's motion at a constant speed. The rate at which this work is being done can be calculated using the equation P = Fd/t, where F is the force, d is the distance, and t is the time. Since the bar is moving at a constant speed, we can use the equation d/t = v, and substitute in the value for F = mg to get P = mgv.

I hope this helps to clarify the concept of electromagnetic induction and how it applies to this problem. If you have any further questions, feel free to ask your teacher or consult additional resources for