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Solving an Integral Problem with Trig Substitution
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[QUOTE="Temp0, post: 4656277, member: 488402"] [h2]Homework Statement [/h2] [url]http://i.imgur.com/u1De0i3.png[/url] [h2]Homework Equations[/h2] [h2]The Attempt at a Solution[/h2] So I notice that the bottom is in the form x^2 - a^2 where a = 7, so I use trig substitution to start this off. x = 7secθ, dx = 7secθtanθ, and finally, x^2 - 49 = 49sec(θ)^2 - 49 = 49 tan^2(θ) Substituting into the integral, I get 7∫(sec^2(θ) - secθ) dθ, which basically turns into: 7tanθ - 7 ln |secθ + tanθ|. After putting x back into the equation, I end up with: √(x^2-49) - 7 ln|(x/7) + (√(x^2-49)/7)| + C I would just like your help in checking my answers, because I don't get any of the answers provided in the multiple choice, and I'm always hesitant to pick "none of the above". Thank you. [/QUOTE]
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Solving an Integral Problem with Trig Substitution
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