Hi this problem stumps me.(adsbygoogle = window.adsbygoogle || []).push({});

Two bricks each having a mass of 0.2 kg tied at the end of a light flexible cord and are passing over a small frinctionless pulley. A 0.1kg block is placed on one of the blocks and removed after 2 seconds. How far will each block move in the first second the 0.1kg block is removed?

My Work:

for one of the blocks: [tex] 0.3(10) - T = 0.3a [/tex]

for the other block: [tex] T - 2 = 0.2a[/tex]

solving, [tex]a = m/s^2[/tex]

Then I found the velocities of each block after the 0.1kg block is removed. i,e [tex] v = 2(2) = 4m/s [/tex]

actually, one of the blocks will have 4m/s and the other -4m/s.

for the block that has -4m/s velocity,

the displacement in the first second:

[tex]s = -4(1) - \frac{1}{2}(10)(1)[/tex]

[tex] = -9m [/tex]

and for the other block i got the displacement as 1m.

BOOK SOLUTION:my book says the correct answer is 4m for each block.

Please tell me where I went wrong. Thanks for your time!

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# Homework Help: Another Laws of Motion question

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