Another linear algebra problem, basis and linear transformations.

Click For Summary
SUMMARY

The discussion focuses on finding the transformation matrix for a linear transformation T: R^3 → R^2 defined by the matrix A = (1,2,3; 4,5,6) with respect to specific bases. The bases for R^3 are given as (1,0,1), (0,2,0), and (-1,0,1), while the bases for R^2 are (0,1) and (1,0). The key steps involve converting vectors from alternate coordinates to standard coordinates using the inverse of the basis matrices, specifically Peb and Beb, to derive the transformation matrix in the desired bases.

PREREQUISITES
  • Understanding of linear transformations and their representations.
  • Familiarity with basis vectors and coordinate systems in linear algebra.
  • Knowledge of matrix operations, including multiplication and inversion.
  • Ability to work with standard and alternate bases in R^n spaces.
NEXT STEPS
  • Study the process of changing bases in linear algebra, focusing on basis transformation techniques.
  • Learn about matrix inversion and its application in transforming coordinates.
  • Explore the concept of linear transformations and their matrix representations in detail.
  • Practice problems involving transformation matrices and basis changes in R^n spaces.
USEFUL FOR

Students of linear algebra, educators teaching linear transformations, and anyone involved in mathematical modeling or computational applications requiring basis transformations.

Gramsci
Messages
64
Reaction score
0

Homework Statement


The matrix A =(1,2,3;4 5 6) defines a linear transformation T: R^3-->R^2 . Find the transformation matrix for T with respect to the basis (1,0,1),(0,2,0),(-1,0,1) for R^3 and the basis (0,1),(1,0) for R^2.

Homework Equations


-


The Attempt at a Solution


I have no idea really. How do I change basis here when I have to basis?
 
Physics news on Phys.org
The matrix you have is a representation of an abstract linear transformation RELATIVE to a specific basis. It's domain and range spaces will both have bases which are indicated by its form. A good starting point would be to examine how that transformation acts on the basis vectors of the second set.
 
I'm not sure I understand. What set?
 
Gramsci said:
I'm not sure I understand. What set?

the basis vectors form a set. {v1, v1, ..., vn} I meant how the transformation acts on {vi} you want to see how the transformation acts on the second set of basis vectors.
 
Ah, it transforms it. I don't see where this is leading me, however :/
 
Gramsci said:
Ah, it transforms it. I don't see where this is leading me, however :/

Does the question specify the representation of T is in the standard bases for R3 and R2?
 
yes,it does.
 
The the general procedure is as follows:
you are given bases, which can be though of as rules transforming a vector from one coordinate system to another. the list of basis elements you are given are the basis vectors of your space written in the standard coordinate system. If you multiply a vector in you 'alternate' coordinates by your basis vectors (as a matrix they can be the columns) you will then convert it to a vector in standard coordinates. In this case you want to take a vector in standard coordinates and convert it to a vector in alternate coordinates.

If {(1,0,1)T, (0,2,0)T, (-1,0,1)T} convert 'alternate vectors' into 'standard vectors' then the inverse of this matrix will take 'standard vectors' to alternate vectors. and likewise for the range space. The transformation matrix (given in standard coordinates) must then be transformed as well, given the inverse elements dimensions you will hopefully see the way to do this.

you have a few elements to look at: Te (that is, T in the standard basis), Peb ={(1,0,1)T, (0,2,0)T, (-1,0,1)T} (take these as the columns of a 3x3 matrix and Beb ={(0,1)T, (1,0)T}. What you want is Pbe and Bbe. Fortunately these are the inverses of Peb and Beb. Hopefully you have it from here!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K