(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Use the primes function to create a list of all the primes below 100. Now use a for loop to multiply adjacent values together. For example the first 4 primes numbers are

2 3 5 7

your calculation would be

2*3 3*5 5*7

which gives

6 15 35

2. Relevant equations

3. The attempt at a solution

Ok I spent a very long time trying to solve this problem. I eventually solved it with the following program.

PLEASE CHECK SECOND POST

i uploaded a easier version to read, i myself couldn't stand even looking at my program below so i took a snip of it in a easier to read form

z=0;

a=length(primes(100));

for b=primes(100);

if z>1;

y=y-1;

else

y=a;

end

b=primes(100);

c(y)=b(y).*b(y-1);

z=z+1;

end

d=find(c>0);

c(d)

which produces the following results, just the way I wanted them to

ans =

Columns 1 through 9

6 15 35 77 143 221 323 437 667

Columns 10 through 18

899 1147 1517 1763 2021 2491 3127 3599 4087

Columns 19 through 24

4757 5183 5767 6557 7387 8633

my only question and concern is why in my program must I include b=primes(100); after the end statement? I thought it was enough for me to just define it once and only once after the for command? I however noticed when I did so that b would get defined as 2 for some strange reason and that's it not what primes(100) is suppose to produce.

I was hoping someone could explain this to me. Thanks in advance!

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# Homework Help: Another Noob MATLAB Question - For loop

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