Another simple vector question

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Homework Help Overview

The discussion revolves around finding a unit vector from point P = (1, 2) to point Q = (4, 6), with participants questioning the definition and calculation of unit vectors and their properties.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the concept of unit vectors, questioning why the answer provided in the book is expressed as a fraction rather than a whole number vector. They also discuss how to find another vector in the same direction with a different magnitude.

Discussion Status

There is an ongoing exploration of the properties of vectors, including their direction and magnitude. Some participants have provided insights into how to scale vectors while maintaining direction, but no consensus has been reached on the specific calculations or interpretations of the problem.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for discussion. The original question has been altered in hypothetical scenarios, prompting further inquiry into the implications of such changes.

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Homework Statement


Find a unit vector from the point P = (1, 2) and toward the point Q = (4, 6).


Homework Equations





The Attempt at a Solution



The answer at the back of the book says 3/5i + 4/5j, shouldn't it just be 3i + 4j?
 
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-EquinoX- said:
The answer at the back of the book says 3/5i + 4/5j, shouldn't it just be 3i + 4j?
A unit vector has length 1.
 
so what do you mean? If I am asked to find another vector that has the same direction with length 10, how do I do that? if I changed the question to (3,6) instead of (4,6) what would be the answer then
 
-EquinoX- said:
so what do you mean? ... if I changed the question to (3,6) instead of (4,6) what would be the answer then
Multiplying a vector by a nonzero scalar does not change its direction. If the length of a nonzero vector v is a, then (1/a)v has length 1.

The following is then an exercise for you.
-EquinoX- said:
If I am asked to find another vector that has the same direction with length 10, how do I do that?
 
ok so if that's so then finding another vector that has the same direction as 3/5i + 4/5j, will be something like

1/10 (3/5i + 4/5j) am I right?

the answer at the back of the book is 6i + 8j, I don't where that came from...
 
Last edited:
-EquinoX- said:
ok so if that's so then finding another vector that has the same direction as 3/5i + 4/5j, will be something like

1/10 (3/5i + 4/5j) am I right?
Come on, Equi, what is the length of that vector?

You have \textstyle\mathbf{v} = (\frac{3}{5}, \frac{4}{5}), which has length

.\; \; \; \; \; \textstyle ||\mathbf{v}|| = \left\|\frac{1}{5}(3, 4)\right\| = \frac{1}{5}||(3, 4)|| = \frac{1}{5}\sqrt{3^2+4^2} = \frac{1}{5}5 = 1.

Hence \textstyle 10\mathbf{v} = 10(\frac{3}{5}, \frac{4}{5}) = (6,8) has length 10 since

.\; \; \; \; \; ||10\mathbf{v}|| = 10||\mathbf{v}|| = 10.
 

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