- #1

- 784

- 11

## Homework Statement

Find a nonzero vector normal to the plane -5x -y +z +9 = 0

## Homework Equations

## The Attempt at a Solution

so the direction of the vector would be (a,b,c) = (-5,-1,1)

I'm not exactly sure what the final form should look like..

is r = ri + tv on the right track? where i plug (-5,-1,1) in for v and for ri i can plug in any numbers that make -5x - 6 + z +9 = 0?

If so I could theoretically plug in (1,4,0)

so

r= (1i + 4j + 0k) + t(-5i -1j +1k)

r = (1-5t)i + (4-t)j + (t)k

The internet program says i'm wrong.. halp?