Another SUVAT and Newton's Second Law Question

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SUMMARY

The discussion centers on calculating the additional retarding force due to brakes on a car with a mass of 1500 kg, experiencing a constant resisting force of 980 N. The car, initially traveling at 48 km/h (13.3 m/s), is brought to rest over a distance of 50 m. Using the SUVAT equation, the deceleration is calculated to be 1.77 m/s², leading to a net retarding force of 2655 N. To find the additional force due to the brakes, the constant resisting force of 980 N must be subtracted from the net force, resulting in a brake force of 1675 N.

PREREQUISITES
  • Understanding of SUVAT equations, specifically v² = u² + 2as.
  • Familiarity with Newton's Second Law, F = ma.
  • Ability to convert units, particularly from km/h to m/s.
  • Basic knowledge of forces acting on moving objects.
NEXT STEPS
  • Study the application of SUVAT equations in various motion scenarios.
  • Explore advanced concepts in Newton's Laws of Motion.
  • Learn about frictional forces and their impact on vehicle dynamics.
  • Investigate real-world applications of braking forces in automotive engineering.
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicle motion and braking systems.

Apothem
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Homework Statement



"The constant force resisting the motion of a car of mass 1500kg is 980N. If, when traveling at 48kmhr-1, the car is brought to rest in a distance 50m by applying the brakes, find the additional retarding force due to the brakes (assumed constant)

Homework Equations



SUVAT: v2=u2+2as, rearranged to a=(v2-u2)/2s

Newton's Second Law: F=ma

The Attempt at a Solution



I used suvat (s=50m , u=48kmhr-1=13.3ms-1 [3.S.F.] , v=0ms-1 , a=a , t=t) to calculate the deceleration as 1.77ms-2 [3.S.F.], I then used F=ma, and found the force to be 2655N, is this right?
 
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Apothem said:

Homework Statement



"The constant force resisting the motion of a car of mass 1500kg is 980N. If, when traveling at 48kmhr-1, the car is brought to rest in a distance 50m by applying the brakes, find the additional retarding force due to the brakes (assumed constant)

Homework Equations



SUVAT: v2=u2+2as, rearranged to a=(v2-u2)/2s

Newton's Second Law: F=ma

The Attempt at a Solution



I used suvat (s=50m , u=48kmhr-1=13.3ms-1 [3.S.F.] , v=0ms-1 , a=a , t=t) to calculate the deceleration as 1.77ms-2 [3.S.F.], I then used F=ma, and found the force to be 2655N, is this right?

2655N is the net retarding force.

There are two retarding forces acting on the car.You need to deduct the constant force of 980N from the net force to get the force due to brakes .
 
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