Finding an angle with Newton's Second Law

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Mr Davis 97
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Homework Statement


Given the free-body diagram below, and that the body is in equilibrium, find θ.
Handwritten free-body diagram with a vertical and horizontal axis meeting at the origin; three forces F1, F2 and F3 act from the origin, F1 and F2 at angles of theta/2 on either side of the vertical, F3 pointing straight down; the labels read F1 = F2 = F3 and theta is marked across the top.

Homework Equations


F = ma

The Attempt at a Solution


[/B]
Basically, I used Newton's second law in the y direction.

Here is my work:
Handwritten physics working on lined paper: force balance sum of F-vectors = 0, sum of F_y = F1 sin(θ/2 - 90°) + F3 sin(θ/2 + 90°) - F2 = 0, leading to 2F sin(θ/2 - 90°) = F, sin(θ/2 + 90°) = 1/2, then a = θ/2 - 90°, sin(a) = 1/2, a = 30°, θ/2 = 120°, θ = 240°.

This does not seem like the correct answer, because the angle is acute. Thus, what am I doing wrong?
 
Last edited:
Mr Davis 97 said:

Homework Statement


Given the free-body diagram below, and that the body is in equilibrium, find θ.
[ IMG]http://i.imgur.com/ee3VjBf.jpg[/PLAIN]

Homework Equations


F = ma

The Attempt at a Solution


[/B]
Basically, I used Newton's second law in the y direction.

Here is my work?
[ IMG]http://i.imgur.com/o4KjcyS.jpg[/PLAIN]
This does not seem like the correct answer, because the angle is acute. Thus, what am I doing wrong?
First of all, the three forces may have equal magnitude, but they are not equal as vectors.

That should be cos(θ/2) or equivalently sin(90° - θ/2)
 
SammyS said:
First of all, the three forces may have equal magnitude, but they are not equal as vectors.

That should be cos(θ/2) or equivalently sin(90° - θ/2)
So θ = 120 degrees?
 
Last edited:
Mr Davis 97 said:
So θ = 120 degrees?
Yes.