Another vector identity question

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SUMMARY

The discussion centers on the vector identity involving the gradient of the function \( r^n \), where \( r = \| \mathbf{r} \| \) and \( \mathbf{r} = xi + yj + zk \). The identity to prove is \( \nabla (r^n) = nr^{n-1} \hat{r} \). Initially, there was confusion regarding the exponent on the right-hand side, but it was clarified that the correct expression is indeed \( n-1 \), paralleling the differentiation rule for polynomials. The use of standard vector identities, including grad, div, and curl, is emphasized as essential for deriving this result.

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  • Familiarity with the notation and properties of unit vectors.
  • Knowledge of polynomial differentiation rules in calculus.
  • Ability to manipulate and apply standard vector identities.
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  • Study the derivation of the gradient of scalar fields in vector calculus.
  • Learn about the application of the product and quotient rules in higher dimensions.
  • Explore the implications of vector identities in physics, particularly in electromagnetism.
  • Review examples of using grad, div, and curl in practical problems.
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Students of mathematics and physics, particularly those studying vector calculus, as well as educators and professionals seeking to reinforce their understanding of vector identities and their applications.

Benny
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Hi, I'm stuck another vector identity question. It's of a different kind to the other one I asked about and looks so much easier but I just can't see what I need to do.

I am told to use standard identities to deduce the following result. The standard identities being referred to are listed in my notes and as I'm sure you can appreciate, it would be a PITA to type them all out. It's just the usual list comprised of various combinations of grad, div curl, and higher dimensional equivalents of product and quotient rules.

Anyway here is the identity I need to show.

[tex] \nabla \left( {r^n } \right) = nr^{n - 2} \mathop r\limits^ \to [/tex]

where [itex]r = \left\| {\mathop r\limits^ \to } \right\|[/itex] and r = xi + yj + zk.

I haven't written this down but from a quick look at the relation, I would've thought that the RHS should have an (n-1) rather than an (n-2) as given. In any case, grad(r^n) looks so simple to compute that I don't see how I do it without just writing out an explicit expression for the gradient. I can't think of any identities which could help - I'm told to use identities for this question.

Any help would be good thanks.

Edit: The (n-2) is probably right now that I think about it. Anyway I'm off to sleep.
 
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If you write it with the unit vector [itex]\hat r[/itex] it's:

[tex]\nabla (r^n)=nr^{n-1}\hat r[/tex]

which ofcourse reminds you of [itex]d/dx (x^n)=nx^{n-1}[/itex], so this is, as you can guess, proved in a very similar way.
 
Thanks for the suggestion, I'll see what I can come up with.
 

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