How to find the curl of a vector field which points in the theta direction?

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SUMMARY

The discussion focuses on calculating the curl of a vector field represented in spherical coordinates, specifically $$\mathbf A = \frac{\mu_0~n~I~r}{2} ~\hat \phi$$. The curl is computed using the formula for spherical coordinates, yielding results for each component: $$(curl~\mathbf A)_r = \frac{\mu_0 ~n~I}{2} \cot\theta$$, $$(curl~\mathbf A)_{\theta}= \mu_0~n~I$$, and $$(curl~\mathbf A)_{\phi}= 0$$. Participants clarify the significance of the variables involved, particularly $$r$$ and $$\sin\theta$$, and discuss the conversion of the curl into Cartesian coordinates using a Wikipedia reference for unit vector conversions.

PREREQUISITES
  • Understanding of vector calculus, specifically curl operations.
  • Familiarity with spherical coordinate systems and their notation.
  • Knowledge of unit vector conversions between spherical and Cartesian coordinates.
  • Proficiency in mathematical notation, including LaTeX for equations.
NEXT STEPS
  • Study the derivation of curl in spherical coordinates.
  • Learn about vector field transformations between spherical and Cartesian coordinates.
  • Explore the implications of vector magnitudes in different coordinate systems.
  • Review the Pythagorean theorem as applied to vector magnitudes in spherical coordinates.
USEFUL FOR

Students and professionals in physics and engineering, particularly those dealing with electromagnetism and fluid dynamics, will benefit from this discussion on vector fields and curl calculations.

  • #31
Well we all are humans, we can do mistakes. No one is perfect.

@benorin The fact that you admitted your mistake I believe it says a lot about your ethos.
 
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  • #32
@Delta2 thanks. Bonus points for quoting he who was my hero during my romance with philosophy in college: Socrates.
 
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  • #33
I think a Cartesian coordinate system is actually defined as an affine coordinate system with origin ##O## and an orthonormal basis {##\vec{e}_x, \vec{e}_y, \vec{e}_z##} where the coordinates of ##P## are a tuple containing the components of the position vector ##\overrightarrow{OP} = x\vec{e}_x + y\vec{e}_y + z\vec{e}_z##.

Part of the confusion might be because it is not obvious how a polar/spherical coordinate system is defined, because the basis vectors depend on the position. I.e. we can only say ##\overrightarrow{OP} = r\hat{r}##, and the components of this vector evidently don't give us the coordinates.

Perhaps someone (@Orodruin/@Delta2) might be able to elaborate on how the mapping from ##A## to ##\mathbb{R}_n## is achieved for polar coordinates?
 
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  • #34
etotheipi said:
Part of the confusion might be because it is not obvious how a polar/spherical coordinate system is defined, because the basis vectors depend on the position. I.e. we can only say ##\overrightarrow{OP} = r\hat{r}##, and the components of this vector evidently don't give us the coordinates.

This is the key issue. In a Cartesian coordinate system, the coordinates also happen to be the components of the position vector. This is generally not true. A coordinate transformation is defined as a 1-to-1 map between two different sets of coordinates. It has no a priori relationship to the components of the position vector, but is just a function from an n-tuple of numbers to another n-tuple of numbers. For example, relating polar coordinates on ##\mathbb R^2## to Cartesian coordinates,
$$
x = \rho \cos\phi, \quad y = \rho \sin\phi.
$$
 
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