Answer: Calculate Net Force of Water on Dam of Width 'w' and Depth 'd

Click For Summary

Homework Help Overview

The discussion revolves around calculating the net force exerted by water on a dam, specifically focusing on the relationship between depth and pressure in a fluid context. The original poster presents an attempt to derive an expression for the net force based on the dimensions of the dam and the water depth.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the net force using pressure and area, integrating pressure over depth. They express uncertainty about the correctness of their approach and the potential need for gravitational considerations. Other participants question the relationship between pressure and depth and seek a precise formula for pressure as a function of depth.

Discussion Status

The discussion is active, with participants exploring different aspects of fluid pressure and its implications for calculating force on the dam. Some guidance has been offered regarding the formula for pressure, but there is no explicit consensus on the approach to take.

Contextual Notes

Participants are grappling with the integration of pressure and the role of gravitational force in their calculations. There is a mention of needing to relate pressure to the specific problem context, indicating potential gaps in information or understanding.

forty
Messages
132
Reaction score
0
Water stands at depth 'd' behind a dam of width 'w'.

i.
Find an expression for the net force of the water on the dam.

ii.
Evaluate the net force on a 100m high dam with a 60m water depth.

Attempt
For the first part:

p=F/A
A=wd
pwd=F

Then integrate from 0 to d which gives .5pw(d^2).
Does this even look remotely correct, i have a feeling there should be a g somewhere in there?

As for the 2nd part I'm stumped, how do I find the p term from that information.

Any help as always is greatly appreciated :)
 
Physics news on Phys.org
forty said:
Then integrate from 0 to d which gives .5pw(d^2).
Does this even look remotely correct, i have a feeling there should be a g somewhere in there?
How does pressure in a liquid depend upon depth?
 
Weight of the water above it?
 
forty said:
Weight of the water above it?
Give a precise formula for pressure as a function of distance below the surface. (Look it up!)
 
P = Po + pdg

p = density

But how do i relate that to what I'm doing >.<
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 7 ·
Replies
7
Views
16K
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
9K
Replies
1
Views
18K
  • · Replies 8 ·
Replies
8
Views
6K