Finding the Net Force Exerted by Water (of certain depth) on A Dam

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SUMMARY

The discussion focuses on calculating the net force exerted by water on a 200-meter high dam with a water depth of 60 meters. The relevant equations include hydrostatic pressure (P = F/A) and the hydrostatic pressure formula (p = rho * g * h + p_atm). The atmospheric pressure cancels out in the calculations, simplifying the net force equation to F = integral(rho * g * h) * w dy, integrated from y=0 to y=200. The width of the dam is crucial for determining the net force, which remains constant despite the lack of specific width information.

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  • Knowledge of fluid mechanics and forces
  • Basic grasp of atmospheric pressure effects
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Beginner@Phys
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Homework Statement

Evaluate the net force on a 200 -m high dam with a 60 mwater depth.

Homework Equations


P=F/A
p(hydrostatic pressure)=rhogh+patm

The Attempt at a Solution


The atmospheric pressure acts on both the dam and the water, so it cancels out of the equation. g=9.8m/s^2, rho=1,000 kg/m^3,d=60m

F=P*A => dF= integral(rhogh)*(wdy) = rho*g*d*w (y) Integrated from y=0 to y=200
=(1,000 kg/m^3 *9.8m/s^2*60m*200 w )-0

But, I was not given width, so how else can I find the net force acting on the dam. All I know is that it remains constant.
 
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Beginner@Phys said:

Homework Statement

Evaluate the net force on a 200 -m high dam with a 60 mwater depth.
Are you sure that 200 m is not the width of the dam? The only height that matters is the depth of the water.

F=P*A => dF= integral(rhogh)*(wdy) = rho*g*d*w (y) Integrated from y=0 to y=200
=(1,000 kg/m^3 *9.8m/s^2*60m*200 w )-0
Not sure what you're doing here.
 

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