Answer: First Order Reaction Rate Constant at 593K

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The first-order reaction SO2Cl2 --> SO2 + Cl2 has a rate constant of 2.20 x 10-5 s-1 at 593 K. After 2.00 hours, the remaining percentage of the initial SO2Cl2 is calculated using the formula ln [a]t/[a]0 = -kt. The calculation yields a remaining amount of approximately 85.4%, confirming option d as the correct answer. The discussion concludes that the calculations are accurate and consistent with the established kinetics principles.

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The first-order reaction, SO2Cl2 --> SO2 + Cl2, has a rate constant equal to 2.20 x 10-5 s-1 at 593 K. What percentage of the initial amount SO2Cl2 will remain after 2.00 hours?


a.1.00%

b.14.7%

c.17.1%

d.85.4%

ln [a]t/[a]0 = -kt

ln [a] = -(2.20 x 10-5 s-1)(7200 s)

ratio of a = e^-0.1584 = 0.8535

Is this correct? Thanks.
 
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