Answer: Volume of 4π/3 x 6495kg/m³ x 0.026m³ in kg

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SUMMARY

The calculation of the volume of a substance with a density of 6495 kg/m³ and a volume of 0.026 m³ results in a mass expressed in kilograms. The formula used is 4π/3 × 6495 kg/m³ × (0.026 m)³. The significant figures are determined by the least precise measurement, which in this case is 0.026 m, dictating that the final answer should be presented with two significant figures after computation.

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Express the answer with the correct units and to the correct number of significant digits:

4pi/3(6495 kg/m^3)(0.026m)^3

-I know that the units in the answer would be kg because the m^3's will cancel.
-It is the sig figs that are giving me trouble. (perhaps the "pi" is screwing me up)

Thanks
 
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The "4" and the "3" seem to be integers and have unlimited significant figures, thereby not limiting the figures in the result. The 0.026 seems to have the fewest, therefore, TWO significant figures. Adjust your answer to two significant figures (AFTER performing your computation, not before).
 

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