Any hints on how to do I find the x component?

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Homework Help Overview

The discussion revolves around finding the x component of a force in the context of calculating work done. The original poster is unsure how to extract the x component from a resultant force that is not explicitly defined in terms of its components.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the nature of the force, noting that it points in the x direction and questioning the implications of this on the calculation of work. There is an exploration of the need for integration due to the force not being constant in magnitude.

Discussion Status

The discussion is ongoing, with participants providing hints and questioning the arithmetic involved in the calculations. There is no explicit consensus on the correct approach, but some guidance on the necessity of integration has been offered.

Contextual Notes

Participants are grappling with the implications of a non-constant force and the need for integration to determine work done over a distance. The original poster expresses confusion over the calculations despite having what they believe is all the necessary information.

warnexus
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Homework Statement



force.png


Homework Equations



Work = F xcomponent * delta x

The Attempt at a Solution


The force is given as a resultant since it does not give a specificed x or y component. Any hints on how to do I find the x component?
 
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It states that the force points in the x direction.
 
Doc Al said:
It states that the force points in the x direction.

if that's the case the force would 33.5N , the work will be (33.5N)(16m) = 537 J which was wrong. I do not get where did I go wrong if all the information is given.
 
warnexus said:
if that's the case the force would 33.5N , the work will be (33.5N)(16m) = 537 J which was wrong. I do not get where did I go wrong if all the information is given.
The force is not constant in magnitude. It increases from 0 (at x=0). You'll need to use integration.
 
haruspex said:
The force is not constant in magnitude. It increases from 0 (at x=0). You'll need to use integration.

if I have to use integration on force then it will be (2(ax^(5/2))/5 .

plugging in the value of a and x= 16m I got 214.6 J <- which is wrong. where did I go wrong?
 
warnexus said:
if I have to use integration on force then it will be (2(ax^(5/2))/5 .
That looks OK.
plugging in the value of a and x= 16m I got 214.6 J <- which is wrong.
Double check that arithmetic.
 

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