corona7w Messages 11 Reaction score 0 Thread starter Apr 30, 2010 #1 I am absolutely stoned by this equation. I've looked through all the trig identities and the only one that comes close to be used in here is sin2u = 2sin(u)cos(u), but there is that lamba... Any suggestions? Attachments Screen shot 2010-04-29 at 9.54.35 PM.png 1.9 KB · Views: 566
I am absolutely stoned by this equation. I've looked through all the trig identities and the only one that comes close to be used in here is sin2u = 2sin(u)cos(u), but there is that lamba... Any suggestions?
D H Staff Emeritus Science Advisor Homework Helper Insights Author Messages 15,524 Reaction score 771 Apr 30, 2010 #2 The λ in that integral is just another constant, no different than 2. Hint: What is sin(a+b) + sin(a-b)?
The λ in that integral is just another constant, no different than 2. Hint: What is sin(a+b) + sin(a-b)?