AP Physics CH 5: Centripetal Motion

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SUMMARY

The discussion focuses on deriving the minimum speed (Vmin) required for a ball to maintain its circular path at point Z in a centripetal motion scenario. The key equations utilized include V≤(2∏r)/(t) and V=√(GM1)/(r). The solution involves equating the expressions for velocity and time, ultimately leading to the conclusion that the time period t can be expressed as t=2∏√(r³)/(Gm1). The importance of maintaining the radius of the ball's path equal to the radius of the track is emphasized, particularly at the top of the circular loop.

PREREQUISITES
  • Understanding of centripetal motion principles
  • Familiarity with the equations of motion in circular paths
  • Knowledge of gravitational force and its effects on motion
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Learn about the forces acting on objects in circular motion
  • Explore the concept of gravitational potential energy in circular paths
  • Investigate the relationship between speed, radius, and gravitational force in circular motion
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Students studying AP Physics, particularly those focusing on mechanics and centripetal motion, as well as educators looking for effective teaching strategies in physics problem-solving.

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Homework Statement



Derive an expression for Vmin, the minimum speed the ball can have at point Z without leaving the circular path.


Homework Equations


V≤(x/t)
V≤(2∏r)/(t)
V=√(GM1)/(r)


The Attempt at a Solution


I set 2∏r = to x since its in a circle. i then had V≤(2∏r)/(t)
then i had (2∏r)/(t)=√(GM1)/(r)
in the end i got t=2∏√(r3)/(Gm1)
it didnt make sense to me so i came here for help /:
 
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The key equation here are v.v=-a.r , and ΣF=ma .
Is "z" the top of a circular loop? if so, then a fast ball would be pushed down by the track (helping mg to accelerate the ball's mass downward). too slow, and the radius of the ball's path, given by r = -v.v/g , would be too small to stay on the track. you want the radius of the ball's path to be the same as the Radius of the track.

They want the speed, not the time.
 
point "z" is about 90 degrees there are also points "M, P, and Q". "Q" is about 270 degrees. "P" is 180 and m is about 60.


idk if that helps
 
Last edited:
90 degrees? from where? from horizontal? then that is the TOP. are you trying to hide important aspects of the question from yourself?
 

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