AP PHYSICS ~ FLUIDS ~ A cube of osmium with a volume of

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving the density of a cube of osmium placed in fresh water, with specific attention to the apparent weight and the application of Archimedes' principle.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants explore the calculation of density based on apparent weight and volume conversion. Questions arise regarding the application of Archimedes' principle and the relevance of the cube being submerged in water.

Discussion Status

The discussion includes attempts to clarify volume conversion and its implications. Some participants express uncertainty about the relevance of the cube's placement in water, while others provide corrections regarding unit conversions. There is no explicit consensus on the interpretation of the problem's conditions.

Contextual Notes

Participants are navigating potential errors in unit conversion and the implications of Archimedes' principle, with some confusion about the correct volume conversion from cm³ to m³.

Silverbolt
Messages
24
Reaction score
0
A cube of osmium with a volume of 166 cm³ is placed in fresh water. The cube's apparent weight is 35.0 N. What is the density of osmium?This is what I did:

I converted force to mass by : 35 N / 9.8 = 3.57 kg

then changed the 166 cm³ to m³ which is : .000166 m³

After that i divided the mass and the volume: (3.57 kg)/(.000166 m³)

And so I got the density as 21506 kg/m³
PLEASE HELP ME IF I'M WRONG
 
Physics news on Phys.org
What did you do with the Archimedes principle/force ?
 
Your conversion from cm^3 to m^3 was off, it's actually 1.66m^3, you move it two decimal places to the left.
 
Silverbolt said:
then changed the 166 cm³ to m³ which is : .000166 m³

That is correct, and iilego's post #3 is wrong.

The question says "the cube was placed in fresh water". You haven't used that information anywhere. What difference does it make if the cube is in water or in air?
 
cm equals .01 meters, which is two decimal places to the left, am I wrong? I never mentioned anything about the answer, just that his conversion was off on the volume.
 
If 1 cm = 0.01 m, then (1 cm)^3 = 1 cm^3 = (0.01 m)^3 = 10^(-6) m^3

1m^3 is rather a large volume
 
never mind, I was wrong, the conversion was right, sorry :(
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
799
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
26
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K