AP PHYSICS ~ Thermal Properties ~ A heat transfer of

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SUMMARY

The discussion focuses on calculating the mass of a block of ice that requires a heat transfer of 9.5 x 105 J to convert from -15°C to water at 15°C. Participants confirm the use of the equations Q = mcΔT and Q = mL for this calculation. The specific heat capacity of ice and the latent heat of fusion are essential for solving the problem accurately. The discussion emphasizes the importance of applying these equations correctly to determine the mass of the ice.

PREREQUISITES
  • Understanding of the specific heat capacity of ice
  • Knowledge of latent heat of fusion
  • Familiarity with the equations Q = mcΔT and Q = mL
  • Basic concepts of heat transfer
NEXT STEPS
  • Study the specific heat capacity of water and ice
  • Learn about latent heat calculations in thermodynamics
  • Practice problems involving Q = mcΔT and Q = mL
  • Explore real-world applications of heat transfer in physics
USEFUL FOR

Students studying AP Physics, educators teaching thermodynamics, and anyone interested in understanding heat transfer principles.

Silverbolt
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A heat transfer of 9.5 x 10^5 J is required to convert a block if ice at -15°C to water at 15°C. What is the mass of the block of ice?

So do I have to use the equation; Q= mcΔT ? and Q= mL ? And if so how do I use it?
 
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Silverbolt said:
So do I have to use the equation; Q= mcΔT ? and Q= mL ? And if so how do I use it?

Yes and Yes and Tell us how you think you would use these equations.
 

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