Application of Coloumb's Law to electroscope

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SUMMARY

The discussion focuses on applying Coulomb's Law to determine the total charge (Q) on an electroscope with two charged balls at the ends of 75-cm wires, each making a 30-degree angle with the vertical. The user correctly identifies that the system is in static equilibrium, where the net force equals zero. The downward gravitational force (mg) must be balanced by the horizontal electrical repulsion force between the charged balls, requiring the application of trigonometric principles to resolve the forces involved.

PREREQUISITES
  • Coulomb's Law for calculating electrical forces
  • Static equilibrium concepts in mechanics
  • Basic trigonometry for resolving forces
  • Understanding of gravitational force (mg) and tension in strings
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  • Explore advanced trigonometric techniques for force resolution
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Theelectricchild
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Hi there, I am having a bit of difficulty with this problem dealing with a little more difficult application of Couloumbs Law.

A large electroscope has two wires that are 75-cm long w/22g balls at the ends. When charged, all the charge resides on the balls (Q/2 for each ball) If the wires each make a 30 degree angle with the vertical, what total charge Q must have been applied to the electroscope?

So I set up my free body diagrams and I know how to figure out the weight force and i believe i can get tension--- but what should I be doing to know how much force electrical force is applied (Repulsion in this case since both charges are positive) to make that 30 degree angle to the vertical?

I need to be thinking back to mechanics a little bit =P

Any help would be appreciated--- thank you.
 
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but what should I be doing to know how much force electrical force is applied

Use Coulomb's Law. Also observe the system is in static equilibrium.
 
yes net force is = to 0 because a = 0. Thank you I noticed that actually right after i posted this--- silly me.
 
Down ward force = mg applied to each side this must be resolved horizontally to equal the charge force which opposes it -- a little trigonometry.
 
There is no horizontal component of a downward force.
 
John not directly your right , but the leaves are held apart by a horizontal force and they are trying to fall due to a vertical force , obviously something connects these two.
 
It isn't the force of gravity, but rather the tension in the leaves, that has the horizontal force component that opposes the charge force.
 

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